Figure 1. Cross section of two concentric charged spherical shells. This inner shell has radius r and charge +Q and the outer shell has radius r+d and charge −Q.

Sunday, 26 August 2018

1:11 AM

Untitled picture.png Machine generated alternative text: Question: -Q Figure 1 _ Cross section of concentric charged spherical shells. This inner Snell has radius r and charge +Q and the outer shell nas radius T + d and charge —Q Two concentric, thin, hollow spheres witn radii r and T + d are charged with equal and opposite charges. +Q is placed on the inner sphere and —Q IS placed on the outer sphere as shown in the diagram. In this problem use rather than Coulomb's constant in your answers. part 1) Write an expression to describe the magnitude ot the electric field between the üo spheres at a radius R, where r < R < r + d. part 2) Write an expression tor the potential between the inner and outer sphere. part 3) Write an expression tor the capacitance ot this system. Check Untitled picture.png Machine generated alternative text: Feedback tor Part 1) -Q Figure 1 _ A spherical Gaussian surface (dashed line) is set up between the two shells of radius R. use Gauss's law to come up witn an expression for E. The Gaussian surface is a sphere with radius R as shown in the figure. In this case: Only the inner sphere is enclosed within the Gaussian surface so qenc — 47rR2 Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 Feedback tor Part 2) The potential is calculated using: AV=-fE. ds. In this case Q 47rR2 1 r+d 47rE0 r4-d r Q(r—r—d) 4TEor(r+d) • Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings            Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings  Ink Drawings Ink Drawings Ink Drawings
Untitled picture.png Machine generated alternative text: Feedback tor Part 1) -Q Figure 1 _ A spherical Gaussian surface (dashed line) is set up between the two shells of radius R. use Gauss's law to come up witn an expression for E. The Gaussian surface is a sphere with radius R as shown in the figure. In this case: Only the inner sphere is enclosed within the Gaussian surface so qenc — 47rR2 Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 Feedback tor Part 2) The potential is calculated using: AV=-fE. ds. In this case Q 47rR2 1 r+d 47rE0 r4-d r Q(r—r—d) 4TEor(r+d) • Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 Untitled picture.png Machine generated alternative text: Feedback tor Part 3) The capacitance is given by: In this case AV 4KEor(r wd) IAVI • Q 4xq] T (T 4TEor(r+d) d Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 A correct answer is , which can be typed in as follows: A correct answer — which can be typed in as follows: 4m Co • r. (r.vd) r • (r4d) A correct answer , which can be typed in as follows:
Untitled picture.png Machine generated alternative text: Feedback tor Part 3) The capacitance is given by: In this case AV 4KEor(r wd) IAVI • Q 4xq] T (T 4TEor(r+d) d Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 A correct answer is , which can be typed in as follows: A correct answer — which can be typed in as follows: 4m Co • r. (r.vd) r • (r4d) A correct answer , which can be typed in as follows:

 

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