A particle with mass 6.68×10−27 kg and charge 3.20×10−19 C is travelling at a speed 3.25×105 ms−1 in a region where the magnetic field is 3.78 T.

Sunday, 26 August 2018

1:12 AM

Machine generated alternative text:
Question: 
part 1) 
A particle witn mass 6.68 x 10¯27 kg and charge 3.20 x 10-19 C is travelling ata speed 3.25 x 105 ms 
Calculate the magnitude of the smallest possible angle 9 beüeen B and F. (Answer in degrees.) 
9 
part 2) 
in a region where the magnetic field is 3.78 T. It accelerates at 3.20 x 10 
ms 
Ittne magnetic field is North and a deuteron (a particle comprising a neutron and a proton) is travelling downwards, in what direction is the magnetic torce on the deuteron? 
(No answer given) 
part 3) 
An electron has velocity i,' = 
Check 
x 105i + 2.8 x 1055) ms—I. A magnetic field B = 1.5i + 2.3j T. Give an expression tor the force F on the electron due to the magnetic field.

 

Machine generated alternative text:
Feedback tor Part 1) 
use the definition of magnetic force: 
so, F = qvBsin(9). 
Newton's first and second law F 
= ma. 
ma = qvB sin(9) 
—1 ma 
9 = sin 
qvB 
Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 
Feedback tor Part 2) 
F = x B, where q is positive. B is north, is down, so F is East. It the thumb ot your right hand is in the direction ot ä and your right index finger in the bdirection, then the middle finger ot that 
hand, fat right angles to the others, is in the direction otä x b. 
Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 
Feedback tor Part 3) 
You have correctly entered the first component 
You have correctly entered the second component 
You have incorrectly entered the third component 
+ t'uj) x (Bri + Bui) and (axi + a.vj + azü) x (bri + bui + = (aubz — azbu)f + (azbx 
Marks for this submissiom 0.22/0.33. This submission attracted a penalty of 0.11 
A correct answer is 32.9, which can be typed in as follows: 
32.9 
A correct answer 
'East" 
A correct answer is 0, which can be typed in as follows: 
A correct answer is 0, which can be typed in as follows: 
A correct answer —1.0e — 14, which can be typed in as follows: 
-I.ee-14 
— axbz)j + (azbu — avbz)ü.

 

 

Created with Microsoft OneNote 2016.