Two positive charges q1=+3.48µC and q2=+5.70µC are fixed in place a distance d cm apart.

Sunday, 12 August 2018

5:06 PM

 

 

Untitled picture.png Machine generated alternative text:
Question: 
Two positive charges qr 
+3.48gC and 
+5.70"C' are fixed in place a distance d cm apart 
Figure 1 _ Two positive charges, qr and q2 are separated by a distance d 
part 1) 
It qr exerts a torce with a magnitude of 1.983 N on 42, what is the distance d beüeen the charges? 
part 2) 
Ittne distance is now doubled, what is the magnitude ot the torce qi exerts on q2 now? 
part 3) 
The charges qr and are now returned to their original separation d. A third charge q3 
in equilibrium? 
4-1.49gC is placed beüeen ql and (h. Where should this charge be placed in order tor it to be 




Untitled picture.png Machine generated alternative text:
Your answer is partially correct Note: Your answers should be correct to 3 significant figures. 
Feedback tor Part 1) 
You have correctly answered this part 
Marks for this submissiom 0.33/0.33. Accounting for previous tries, this gives 0.22/0.33. 
Feedback tor Part 2) 
You have correctly answered this part 
Marks for this submissiom 0.33/0.33. 
Feedback tor Part 3) 
In this case the two forces acting on q3 must be equal so: 
F 13 
47rE0 
47rEo 
where is the position of q3. 
This can be written as 
(d x)2q1 = q2X2 
q2)x2 — 2dq1X + qid2 
(qi — 
This can be solved with the quadratic formula to give: 
We need the solution between O and d as q.3 is placed between qi and so take 
Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 
A correct answer is 0.3, which can be typed in as follows: 
A correct answer is 0.4958, which can be typed in as follows: 
e .4958 
A correct answer is 0.132, which can be typed in as follows: 
e. 132 
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Untitled picture.png Machine generated alternative text:
Your answer is partially correct Note: Your answers should be correct to 3 significant figures. 
Feedback tor Part 1) 
You have correctly answered this part 
Marks for this submissiom 0.33/0.33. Accounting for previous tries, this gives 0.22/0.33. 
Feedback tor Part 2) 
You have correctly answered this part 
Marks for this submissiom 0.33/0.33. 
Feedback tor Part 3) 
In this case the two forces acting on q3 must be equal so: 
F 13 
47rE0 
47rEo 
where is the position of q3. 
This can be written as 
(d x)2q1 = q2X2 
q2)x2 — 2dq1X + qid2 
(qi — 
This can be solved with the quadratic formula to give: 
We need the solution between O and d as q.3 is placed between qi and so take 
Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 
A correct answer is 0.3, which can be typed in as follows: 
A correct answer is 0.4958, which can be typed in as follows: 
e .4958 
A correct answer is 0.132, which can be typed in as follows: 
e. 132

 

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