An uncharged conductive rectangular block lies in a uniform electric field E

Sunday, 12 August 2018

4:11 PM

Machine generated alternative text:
Question: 
Figure 1 _ An uncharged conductive rectangular block lies in a uniform electric field E. A rectangular prism Gaussian surface (dashed line) is set up with halt inside the conductive block and 
half outside. 
A large neutral conducting rectangular block is placed in a uniform electric field Eo = 9.35 NIC so that the electric field lines are perpendicular to the surface ottne block as shown in the 
figure. In this question we will consider a Gaussian surface, a prism witn cross-sectional area A = 6.07 cm2 , one surface inside the block and another parallel to the block and on the left 
hand side as snowm (The Gaussian surface IS tar trom any edge effects, which are negligible.) 
part 1) 
What is the electric flux through the Gaussian prism? 
part 2) 
What is the charge density on the lett hand side of the conducting block? 
C/m2 
part 3) 
What is the surface charge density on the right hand side ottne conducting block? 
C/m2

 

Machine generated alternative text:
Feedback tor Part 1) 
Figure 1 Also the area vectors dA of the Gaussian surface are perpendicular each surface of the rectangular surface. 
The electric flux through a surface is given by 
Inside the conductor the electric field is zero so the flux through this surface is zero. 
The surface on the lett nas an area A and dA points out from the surface, to the left, while E is Eo and goes to the right so: 
= -EDA 
through this surface (negative sign due to opposite directions). 
For the remaining surfaces dA is perpendicular to Eo so the dot product between these is zero and these sides do not contribute to the flux (no electric field lines cut these surfaces). So 
= -EoA. 
Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 
Feedback tor Part 2) 
Gauss's law tells us that 
= fi.dA 
In the previous part we showed that — —m A. We can calculate the charge enclosed inside the Gaussian surface using: 
= -EDA 
-EoAeo. 
The surface charge density is given by: 
-Eoeo. 
Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 
Feedback tor Part 3) 
You have correctly answered this part 
Marks for this submissiom 0.33/0.33.

 

Machine generated alternative text:
A correct answer 
-e.ee568 
A correct answer 
-8.282-11 
—0.00568, which can be typed in as follows: 
—8.28e — 11, which can be typed in as follows: 
A correct answer is 8.28e — 11, which can be typed in as follows: 
8.282-11

 

 

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