A radial electric field is described by

Sunday, 12 August 2018

6:27 PM

Machine generated alternative text: Question: A radial electric field is described by and is directed out trom the origin. Take the electric potential, V, at oo to be 0 (V part 1) Write an expression tor the electric potential a radial distance R trom the origim part 2) Calculate the change in electric potential as a panicle moves from rl = 9.25 cm to Y2 = part 3) 4.81x10 NIC 11.12 cm in this field. It a proton is placed at rest at Tl = 9.25 cm in this field what speed will it nave when it reaches "2 = 11.12 cm? (Apan trom this field, no other forces act on the proton.)

 

Machine generated alternative text: Feedback tor Part 1) The electric potential is related to the electric field through: In this case E 4.81x10-2 cls. . We should consider the case where a test particle is moved along a radial path trom r = DO (as V R 4.81x10Q dr 0 there) to r = -4.81 x 10 2 2r2 = 4.81 x 10 2 2R2 Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 Feedback tor Part 2) 4.81x10-2 1 The electric potential at R is , moving from R = Tl to R = we obtain: AV = 142 4.81 x lo- 4.81x10- 2 Remember to convert Tl and from cm to m. Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 Feedback tor Part 3) The change in electrical potential energy is equal to the gain in kinetic energy so: L m + qAV — 0 2qAV Note that AV here is a negative number as the potential decreases. The mass and charge ot the proton are on your data sheet. Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 0.02405 A correct answer is , which can be typed in as follows: R2 A correct answer —0.866, which can be typed in as follows: -e .866 A correct answer is 12900, which can be typed in as follows: 12gee

 

 

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