A particle with a charge +0.00192 C moves through an electric field
Sunday, 12 August 2018
3:56 PM
Created with Microsoft OneNote 2016.
![Machine generated alternative text:
Question:
A particle witn a charge +0.00192 C moves through an electric field described by:
(6.57 + 7.90x)i - 4.883.
For the case where the particle moves trom = 4.62 m to =
13.78m.
part 1)
Write down an integral expression to describe the change in potential over this path.
AV ¯ f(x) dz.
ml = 462
Your last answer was interpreted as follows: 4.62
13.78
Your last answer was interpreted as follows: 13.78
-E*dX
Your last answer was interpreted as follows: (—E)
The variables found in your answer were: [E, dc]
and < Tu.
part 2)
Solve this expression to calculate AV tor this case
-726
Your last answer was interpreted as follows: —726
part 3)
What is the change in electrical potential energy as the particle moves along this path?
U = -1.39
Your last answer was interpreted as follows: —1 39](A%20particle%20with%20a%20charge%20+0.00192%20C%20moves%20through%20an%20electric%20field_files/image001.png)
