A cube with side length l=9.16 cml=9.16 cm is placed in a constant electric field described by E⃗ =6.84×106j^ N/C.

Sunday, 12 August 2018

4:06 PM

Untitled picture.png Machine generated alternative text: Question: A cube with side length I 9.16 cm is placed in a constant electric field described by E = 6.84 x NIC. Figure 1 _ A cube of side length a sits at the origin of the x, y-axis. A constant electric tield is applied in the y—directiom Side I denotes the side where z = 0 (pink with red edges) and Side 2 is the side where y = I (pale blue). part 1) What is the flux through the surface 1? Note that surface 1 has vertices at the origin, li, li + Ij and Ij . N m2/C Your last answer was interpreted as follows: 0 part 2) What is the electric flux through surface 2? Note that surface 2 has veäices at Ij , li + Ij , li + Ij and Ij — = 57400 N m2/C Your last answer was interpreted as follows: 57400 part 3) What is the net electric flux tnrougn the entire cube? = 57400 N m2/C Your last answer was interpreted as follows: 57400 Untitled picture.png Machine generated alternative text: Your answer is partially correct Note: Your answers should be correct to 3 significant figures. Feedback tor Part 1) You have correctly answered this part Marks for this submissiom 0.33/0.33. Feedback tor Part 2) You have correctly answered this part Marks for this submissiom 0.33/0.33. Feedback tor Part 3) As there is no charge enclosed in this surface the net flux through the surface is zero. Gauss's law tells us that so qenc = 0 tells uS = 0. Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11 Ink Drawings Ink Drawings        Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings Ink Drawings  
Untitled picture.png Machine generated alternative text: Your answer is partially correct Note: Your answers should be correct to 3 significant figures. Feedback tor Part 1) You have correctly answered this part Marks for this submissiom 0.33/0.33. Feedback tor Part 2) You have correctly answered this part Marks for this submissiom 0.33/0.33. Feedback tor Part 3) As there is no charge enclosed in this surface the net flux through the surface is zero. Gauss's law tells us that so qenc = 0 tells uS = 0. Marks for this submissiom 0.00/0.33. This submission attracted a penalty of 0.11

 

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