Rotational Inertia (Week 7)

Wednesday, 18 April 2018

10:58 PM

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The diagram above show's two masses, both with mass m = 569 kg, located r = 989 cm from the axis of rotatiom What is the moment of inertia, I for these masses in kgm2? 
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11M 
Well done 
kg ml 
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During the experiment you will measure the angular acceleration of different objects, pu will use this to work out the moment of inertia of these objects. In order calculate the moment of inertia, l, ofthese objects •pu will need 
to calculate the torque. To calculate the torque you will need to know the tension in the string.To calculate the tension pu vill need to know the linear acceleration of the hanging masses. 
rod and masses 
3-step pulley 
clamp-on Super Pulley 
Stri ng 
support rod 
Mass hanger 
A hanging mass is attached to a string which is wound around a pulley The hanging mass is released from rest and falls to the ground causing the pulley to rotate. The diameter of the pulley is 4.3 mm, the angular acceleration 
is measured to be 37 rads-4 What is the linear acceleration of the hanging mass in ms-2? 
0.0080 
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m_lt of 2.00 
quæt& 
rod and masses 
3-step pulley 
clamp-on Super Pulley 
Stri ng 
support rod 
Mass hanger 
A hanging mass, m= 2851 g, is attached to a string that is wrapped around a pulley of diameter d = 6722 mm This is shown in the photo above. The hanging mass is released from rest As the mass falls the angular 
acceleration is measured to be 1.240 rads-2. The experiment is conducted in Sydney where the acceleration due to gravity is g = 9.797 ms-2. Calculate the tension in the string. 
0.2781 
To calculate the tension in the string you need to use the formula Tension = m(g-a). 
𝑇=𝑚(𝑔−𝑎)


𝑎 = 𝑟×𝛼
𝑎 =﷐0.06722﷮2﷯× 1.240

T = m(g-a)
𝑇 =﷐28.51﷮1000﷯×(9.797 −﷐0.06722﷮2﷯×1.240)
𝑇 = 0.27812427583 𝑁

𝑇 = 0.2781 𝑁

𝑎 = 𝑟×𝛼

𝑇 = 0.2781 𝑁

 

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