Linear Combinations and Spans
Saturday, 11 August 2018
12:58 PM
A span is NOT a linear combination
Linear Combination - constrained within a vector space
Spanning Set
=V![]()
Prove that 1, x, x2 is a spanning set
for ![]()
For any polynomial p(x) in , we can write ![]()
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Equate the coefficients
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…
The system is consistent, there exists ![]()
For one positive linear combination, we choose a value for the
non-leading variable - ![]()
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Hence, ![]()
Revise how to check for solutions of a matrix, one
solution, no solutions, infinite solutions
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