Alg1131W4T1 - Lines and planes

Friday, 23 March 2018

1:29 PM

Untitled picture.png Machine generated alternative text:
In two dimensions, the length ot a vector 
denoted Ivl, is naturally defined as the square root ot the quadrance Q (v) a2 + b2, in other words 
It v = AB then the length of v is also the distance between the points A and B, and we write 
b 
2 
So the length of the vector u = 
—1 
Ivl= AB . 
O . And the distance between the points A = [—2, 2] and B = [—3, —2] is dist(A,B) 
Note: to write the square root of 2 in Maple we would use sqrt (2) 
In three dimensions the story is similar, where the length of the vector 
b 
denoted Ivl, is defined as the square root ot the quadrance Q (v) a2 + b2 + c2 in other words 
So the length of w 
1 
3 
is 
sqrt(1 0) 
O and the distance between the points C = and D = [1, 8,3] is 
sqrt(26) 
An important related idea is that ot the dot product ot two vectors. In three-dimensional space, it 
a2 
bl 
we define 
So for example 
and 
- ald2+b1b2+c102. 
—1 
5 
3 
2 
1 
4 
15 
O , and 
—1 
5 
3 
—1 
5 
3 
VI 
= 35. 
We observe that in general v . v is just the quadrance Q(v) 

Untitled picture.png Machine generated alternative text:
Consider the plane y = 1 in three-dimensional space, together witn the unit cube with vertices O, A, B, C, D, E, F, G as shown below 
Geometrically, a vector u is parallel to a plane it there exist points P and Q on the plane such that u = PQ. 
For example OE is parallel to the plane y = 1 because OE = CF where C and F are öotn on the plane. 
Geometrically this means that OEFC is a parallelogram. 
i) Which of these vectors are parallel to the plane y = 1 ? [select all that apply] 
OD 
D OC 
D GO. 
ii) The vector DC is parallel to the planes [select all that apply) 
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﷐𝑣﷯=﷐﷮𝑄﷐𝑣﷯﷯=﷐﷮﷐﷐﷐𝑥﷮1﷯−﷐𝑥﷮2﷯﷯﷮2﷯+﷐﷐﷐𝑦﷮1﷯−﷐𝑦﷮2﷯﷯﷮2﷯+﷐﷐﷐𝑧﷮1﷯−﷐𝑧﷮2﷯﷯﷮2﷯+…﷯
﷐𝑣﷯=﷐﷮𝑄﷐𝑣﷯﷯=﷐﷮﷐𝑎﷮2﷯+﷐𝑏﷮2﷯+﷐𝑐﷮2﷯+…﷯
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﷐−1×2﷯+﷐5×1﷯+﷐3×4﷯=15
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Untitled picture.png Machine generated alternative text:
Consider the plane y = 1 in three-dimensional space, together witn the unit cube with vertices O, A, B, C, D, E, F, G as shown below 
Geometrically, a vector u is parallel to a plane it there exist points P and Q on the plane such that u = PQ. 
For example OE is parallel to the plane y = 1 because OE = CF where C and F are öotn on the plane. 
Geometrically this means that OEFC is a parallelogram. 
i) Which of these vectors are parallel to the plane y = 1 ? [select all that apply] 
OD 
D OC 
D GO. 
ii) The vector DC is parallel to the planes [select all that apply) 

Untitled picture.png Machine generated alternative text:
Here is another view ot the same unit cube. We see that the diagonal lines OF, EC, AG and DB ottne unit cube meet at the point P in the center. 
i) The point Pis 
ii) The vectors PA, PB and PC are: 
PA 
iii) Evaluate the following dot products: 
O and BC. BE 
An important use of the dot product is defining perpendicularity: 
So we can conclude that 
u I v precisely when u • v = 
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Untitled picture.png Machine generated alternative text:
Here is another view ot the same unit cube. We see that the diagonal lines OF, EC, AG and DB ottne unit cube meet at the point P in the center. 
i) The point Pis 
ii) The vectors PA, PB and PC are: 
PA 
iii) Evaluate the following dot products: 
O and BC. BE 
An important use of the dot product is defining perpendicularity: 
So we can conclude that 
u I v precisely when u • v = 

Untitled picture.png Machine generated alternative text:
3 
2 
o 
0 
05 
2 
3 
4 
5 
G 
The dot product allows us to also define and calculate the angle 9 between vectors v and w by the formula 
v.w= Ivllwlcos(9). 
Here is our unit cube again' 
i) The cosine ot the angle Z ADC is 112 
ii) The triangle AADCis equilateral 
iii) The angle Z BEG is 60 
O degrees. 
iv) The triangle AEBG is equilateral 
v) The two triangles A ADC and AEBG are: 
congruent 
parallel 
similar, but not congruent 
meeting at the center of the cube 
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Untitled picture.png Machine generated alternative text:
3 
2 
o 
0 
05 
2 
3 
4 
5 
G 
The dot product allows us to also define and calculate the angle 9 between vectors v and w by the formula 
v.w= Ivllwlcos(9). 
Here is our unit cube again' 
i) The cosine ot the angle Z ADC is 112 
ii) The triangle AADCis equilateral 
iii) The angle Z BEG is 60 
O degrees. 
iv) The triangle AEBG is equilateral 
v) The two triangles A ADC and AEBG are: 
congruent 
parallel 
similar, but not congruent 
meeting at the center of the cube 

Untitled picture.png Machine generated alternative text:
The dot product is defined between any two vectors VI and v2 in n-dimensional space, and gives us the useful relation 
where 9 is the angle between VI and v2_ 
In two dimensions it v = 
al 
and v 2 ¯ 
a2 
then the dot product is 
Consider the vectors 
¯ IVI IV'21 cos(9), 
VI = ala2 +b1b2- 
2 
0 
i) Then a • b 
2 
2 
3 
3 
4 
3 
and b 
1 
1 
2 
x 
5 
ii) The cosine ot the angle 9 between a and b is cos(9) 
iii) The angle between a and b is, to the nearest degree, 46 
iv) The cosine ot the angle between a and BA is 
1/sqrt(2) 
v) The angle between a and BA is, to the nearest degree, 
vi) The triangle formed by O = [0,0], A = [3,11 and B 
a right triangle 
obtuse 
isosceles 
equilateral 
46 
[1, 2] is a bit special, since it is: [select all that apply] 
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Untitled picture.png Machine generated alternative text:
The dot product is defined between any two vectors VI and v2 in n-dimensional space, and gives us the useful relation 
where 9 is the angle between VI and v2_ 
In two dimensions it v = 
al 
and v 2 ¯ 
a2 
then the dot product is 
Consider the vectors 
¯ IVI IV'21 cos(9), 
VI = ala2 +b1b2- 
2 
0 
i) Then a • b 
2 
2 
3 
3 
4 
3 
and b 
1 
1 
2 
x 
5 
ii) The cosine ot the angle 9 between a and b is cos(9) 
iii) The angle between a and b is, to the nearest degree, 46 
iv) The cosine ot the angle between a and BA is 
1/sqrt(2) 
v) The angle between a and BA is, to the nearest degree, 
vi) The triangle formed by O = [0,0], A = [3,11 and B 
a right triangle 
obtuse 
isosceles 
equilateral 
46 
[1, 2] is a bit special, since it is: [select all that apply] 
Untitled picture.png Machine generated alternative text:
cos 0 

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