Wednesday, 3 April 2019
10:20 AM
Suppose that is a set with elements and is a set with elements.![]()
![]()
First we count all possible functions
from to ![]()
Choose …
ways![]()
Choose …
ways![]()
…
Choose …
ways![]()
There are ways![]()
No repetitions are allowed… ![]()
This is equal to zero, as there are less output elements than input elements
Write ![]()
![]()
Let be the set of all functions from to where is missing![]()
![]()
for ![]()
![]()
![]()
![]()
![]()

If then , else ![]()
Created with Microsoft OneNote 2016.