Prove is irrational
Wednesday, 20 March 2019
10:30 AM
Proof by Contradiction
Suppose that is rational.![]()
Then where and are integers with no common factor.![]()
Squaring both sides
![]()
![]()
Hence is even, so is even. Hence we can write for some integer ![]()
Substituting into the previous equation gives ![]()
And so
![]()
Therefore is even, and hence is even![]()
and have a common factor of ![]()
This contradicts our assumption that and have no common factor![]()
Therefore our original assumption is false
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