Prove  is irrational
Wednesday, 20 March 2019
10:30 AM
Proof by Contradiction
Suppose that  is rational.![]()
Then  where  and  are integers with no common factor.![]()
Squaring both sides
![]()
![]()
Hence  is even, so  is even. Hence we can write  for some integer ![]()
Substituting into the previous equation gives ![]()
And so
![]()
Therefore  is even, and hence  is even![]()
 and  have a common factor of ![]()
This contradicts our assumption that  and  have no common factor![]()
Therefore our original assumption is false
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