Example
Friday, 15 March 2019
7:14 PM
Let . Then![]()
if and only if both and ![]()
Firstly, suppose that ![]()
![]()
-> ![]()
-> ![]()
Therefore and ![]()
Conversely, suppose that and ![]()
![]()
so is even![]()
is even![]()
Hence is even![]()
Therefore for some integer ![]()
![]()
Therefore ![]()
This completes the proof
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