Exercices
Wednesday, 20 February 2019
10:35 AM
Proof (actually write this down)
Suppose that  and  and that ![]()
Then  or ![]()
If , then  because ![]()
If , then  because ![]()
Which proves that ![]()
In both cases,  which proves that ![]()
Proof: Suppose that  and  then ![]()
Let ![]()
Then  since ![]()
Similarly,  since ![]()
Hence ![]()
Thus ![]()
Proof: Suppose that ![]()
By definition, ![]()
Let , since  it follows that ![]()
Then , so ![]()
Hence, ![]()
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