Exercices
Wednesday, 20 February 2019
10:35 AM
Proof (actually write this down)
Suppose that and and that ![]()
Then or ![]()
If , then because ![]()
If , then because ![]()
Which proves that ![]()
In both cases, which proves that ![]()
Proof: Suppose that and then ![]()
Let ![]()
Then since ![]()
Similarly, since ![]()
Hence ![]()
Thus ![]()
Proof: Suppose that ![]()
By definition, ![]()
Let , since it follows that ![]()
Then , so ![]()
Hence, ![]()
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