If the voltage across an impedance is v(t)=160cos(50t)V and the current through it is i(t)=−33sin(50t−30)A, calculate the average power absorbed by the impedance.

Thursday, 11 October 2018

9:55 PM

Machine generated alternative text:
Ittne voltage across an impedance is v(t) = 160 cos(50t) V and the current through it is i(t) = —33 sin(50t 
Hint: Provide 50th the numerical answer in decimal format and the proper unit using standard Sl unit symbols. 
Answer: 1320W 
30) A, calculate the average power absorbed by the impedance.

 

 

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